# Line slope calculator 5x+4y=29

**Straight line given by points A[1; 6] and B[5; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.25x+7.25

**Canonical form of the line equation:**5x+4y-29 = 0

**Parametric form of the line equation:**

x = 4t+1

y = -5t+6 ; t ∈ R

**Slope:**m = -1.25

**Slope angle of line: φ =**-51°20'25″ = -0.8961 rad

**X intercept:**x

_{0}= 5.8

**Y intercept:**y

_{0}= q = 7.25

**Distance line from the origin:**d

_{0}= 4.529

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; -5)

**Normal vector: n =**(5; 4)

**Midpoint of the segment AB: M =**[3; 3.5]

**Perpendicular Bisector equation:**4x-5y+5.5 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (5; 1) ; |OB| = 5.099**

**Scalar product OA .OB = 11**

**Angle ∠ AOB = 69°13'40″ = 1.2083 rad**