Sorry, but can someone help me with my math?
- Locked due to inactivity on Aug 4, '16 4:36pm
Thread Topic: Sorry, but can someone help me with my math?
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It's System of Equations: Elimination
help :( -
Sure, if I remember
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no
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4x + 3y = 1
x - 3y = -11
D: -
4x+3y=1
+4x +4x
3y= 4x+1
/3 /3 /3
y= 4/3x +1/3
^ like that or do I have to include both equations? -
No, no, no. The elimination system, not by substitution.
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Oh okay hmm
I'm trying to think of last year -
I know how if you need help
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I'm in the 6th grade....
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Amara isn't this how you do it?
a] 4x + 3y = 1
b] x - 3y = -11
4x=1
x= -11
5x= -10
x= -2
4(-2)+3y= 1
-8+3y= 1
+8 +8
3y= 9
y=3
Answer:
(-2, 3) -
I suck at math
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Simplifying
4x + -3y = 1
Solving
4x + -3y = 1
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3y' to each side of the equation.
4x + -3y + 3y = 1 + 3y
Combine like terms: -3y + 3y = 0
4x + 0 = 1 + 3y
4x = 1 + 3y
Divide each side by '4'.
x = 0.25 + 0.75y
Simplifying
x = 0.25 + 0.75y -
Simplifying
x + -3y = -11
Solving
x + -3y = -11
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3y' to each side of the equation.
x + -3y + 3y = -11 + 3y
Combine like terms: -3y + 3y = 0
x + 0 = -11 + 3y
x = -11 + 3y
Simplifying
x = -11 + 3y
Alright, there you go -
Anymore Drew?
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